2h^2-10h=-1

Solution for 2h^2-10h=-1 equation:

2h^2-10h=-1

We move all terms to the left:

2h^2-10h-(-1)=0

We add all the numbers together, and all the variables

2h^2-10h+1=0

a = 2; b = -10; c = +1;
Δ = b2-4ac
Δ = -102-4·2·1
Δ = 92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{92}=\sqrt{4*23}=\sqrt{4}*\sqrt{23}=2\sqrt{23}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{23}}{2*2}=\frac{10-2\sqrt{23}}{4}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{23}}{2*2}=\frac{10+2\sqrt{23}}{4}
$